Guide
1
With roulette, measure the length and width of your kitchen, as well as the height of the ceiling.Put the results in meters and multiply.You will receive the amount of food in cubic meters.If the geometry of the space complex, plans to use the BTI - they always indicate your apartment floor area in square meters.For example, the kitchen area - 15 m2, ceiling height - 3 m. The amount of food is 15 x 3 = 45 m3.
2
Calculate the required ventilation, which should provide a hood.To do this, multiply the amount of food in the ventilation rate - the amount of which determin
es how many times per hour the air in the room is completely updated.According to the SNP, the forced ventilation of the kitchen should provide ventilation rate of 10 - 12. In this example, the power drawing be 45 x 12 = 540 m3 / h.
3
determine which mode will work your hood.There are two options: move the air and recycling.
4
Bleeding out is considered to be more effective, but keep in mind some of the subtleties.Use ventilation calculations and get powerful device (600 - 1200 m3 / h) if the duct will be displayed on the street through an exterior wall or the building has ventkanal hood.Most often, in our high-rise residential buildings is provided only natural ventilation.The capacity of air ducts (provided that they are not blocked and not blocked by enterprising neighbors who wanted to increase the area of ​​the kitchen) is typically 150 - 180 m3 / h (if you are very lucky, 300 - 400 m3 / h).Hood greater power to pull harder will not, but will create a "backwater" of air in the system and violate the normal ventilation around the riser.
5
The recirculation air is discharged to the outside, and passed through a dense charcoal filter and back into the room.This mode is used when the air vent is not available ventkanal clogged or blocked.The efficiency of the extraction greatly reduced due to the need to overcome the resistance of the filter.Therefore, increase the computational power 30 - 40%.In our example, we need hood th power of at least 540 x 1.4 = 756 m3 / h.