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Guide
1
To translate a lot of the physical body, given in tons of its weight (in kilonewtons), multiply the number of tons by the number 9,8 (gravitational acceleration).That is, use the following formula: Cr = KKN * g, where: Rm - the number of tons,
KKN - number kN,
g - acceleration due to gravity (≈9,8m / s²) On the dimension of the quantity g (m / s²) attention possibleIt does not pay.For more accurate results, use "exact value of g: 9,806652.
2
example.
in the tank is 60 tons of water.Weight of the empty tank - 1 ton.
Q: What is the weight of the filled tank?
Solution: (60 + 1) * 9.8 = 59.78 (kN).Calculations made by the above formula is valid only for "normal conditions, ie,near the Earth's surface away from the geomagnetic anomalies and provided that the buoyancy of gas (or liquid) can be neglected.
3
If the body is in liquid, it acts buoyant force equal to the weight of the fluid displaced by the body.Therefore, to transfer tons kN body immersed in a liquid, use the following formula: Cr = KKN * g - ENG where: VZ - the weight of the displaced body zhidkosti.Primer.
The water tank is placed a metal workpiece weight 2 tons .The weight of the fluid displaced by the workpiece was 5 kN.
Q: What is the weight of the workpiece in the water?
Solution: 2 * 9.8 - 5 = 14.6 (kN).
4
Since the weight of the displaced fluid depends on the density and volume of the body, you can use the following formula: KKN = Rm * g - On * Pl * g * = g * (Rm - On * RV)where: On - the volume of the body, and pancreas - the density of the liquid,
while the volume of the body should be presented in cubic meters, and the density of the liquid - in tonnes per cubic meter.
5
If instead the scope of known density of the object, use the following formula: KKN = Rm * g - Cr / Fr * RV * g * = Cr * g * (1 - RV / Fr), where:Fri - body density (tonnes per cubic meter).