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Guide
1
Count, based on the number, size of rooms and their purpose, amount and type of lighting load current in the lighting network.To do this, use the formula P = pS, where p is the specific lighting power, measured in watts on meter2 (on average - 20 W), S - area of ​​the premises.Example: There are 5 rooms of 120 square meters.Power is 20 × 120 = 2400 watts.Calculate the load current in the lighting network of 2400: 220 = 10.9 Amps.
2
Calculate the maximum power at the same time operate the appliance in each room.On average, this figure does not exceed 900 watts for living rooms.If the winter will be used for heating oil coolers, too aware of their power.Pay special attention to the kitchen: the majority of energy-consuming equipment to be t
here.At the same time the inclusion of modern electric cooking plate capacity of 3,000 watts, the built-in oven capacity of 3500 watts, the microwave power of 1400 W, an electric power of 2000 watts, the washing machine (a lot of people have a washing machine in the kitchen) Power 2200 watt refrigerator capacity of 400 watts, food processor power1000 W (such a situation may arise when preparing to any family celebration), the load current will rise to: 3000 + 3500 + 1400 + 2000 + 2200 + 400 + 1000 = 13500 220 = 61.5 Amps!
3
With insufficient wire section simultaneous operation of these devices will lead to a power failure at the most inopportune moment.Plus electric water heater in the bathroom capacity of 1000 watts.Just enter in the calculation of the 15 percent reserve.In this case, the maximum load current is obtained: about 11 amps for lighting + on 900 watts for 5 rooms = 4500: 220 = 20.5 Amps maximum consumption in the residential rooms + 61.5 Amps at 4.5 Ampere kitchen + bathroom =97.5: 100 × 115 = 112 amperes.