Guide

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expression magnitude of

**formula**produced by mathematical operations - transfer member, dividing one number both of the recording and other. That is, it should facilitate and work with the formula as aalgebraic equation.Follow these steps, you must also consider the change of sign, the rules of inference value from a root, exponentiation. 2

In the simplest case, when an expression of the form v = 2 * g + 11 g value for the search, follow these steps.Transfer all the members that do not contain the variable g in the single (best left) part of the equation, not forgetting to change their sign when moving to the
opposite: -2 * g = 11 - v.The remaining amount and the constant transfer of the equal sign.If the desired value is worth factor in this case (2) which divide this constant both sides of the equation: g = - (11 - v) / 2.

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When terms of the formula

**magnitude raised to a power, as, for example, in the next version: S = a * t² / 4, follow the steps described above first.Put variable in degree on the left side of the equation, and for the constant output of the denominator, multiply this number both parts****formula**: a * t² = 4 * S.Divide the equation by a variable and you get: t² = 4 * S / a.To hide the extent of the required variable, take the root of the same degree (here square) on both the left and right side of the expression: t = √4 * S / a.The reverse situation occurs when the unknown quantity is under the sign of the root, in this case it is necessary to perform the construction of the entire equation in the extent specified in the bud.Thus, the expression ³√S = v + g is converted into the form S = (v + g) ³. 4

If you have complex expressions derived from multiple substitutions of different formulas, there are often difficulties in terms of the unknown quantity.For example, the design of the form S = (√t² * k / (1 + g)) * f - 15 finding of k is desirable to conduct preliminary simplifying equation by introducing the substitution variable.Take for x expression in large parentheses: x = (√t² * k / (1 + g)), then the original equation will look like this: S = x * f - 15. It is easy to x = (S + 15) / f.Then return for x bracket expression (√t² * k / (1 + g)) = (S + 15) / f.Then you can continue to simplify using similar substitutions or directly express the desired value

**: k = ((1 + g) * (S + 15) / f) 2 / t².** Sources:

- expression values