you need

- - hydrometer;
- - table density of the substance;
- - scales;
- - graduated cylinder.

Guide

1

To measure the density of the liquid mixture

**take a hydrometer.Immerse it in the liquid so that it floats freely in it.At the top of the scale of the hydrometer is.Determine****density****mixture**, combining scale with the bottom of the meniscus of the liquid in which it is immersed. 2

To calculate the density of the mixture
lts were obtained in g / cm³.To put it in kg / m³, the result of multiply by 1000.

**weigh it on the scales.The value of the mass m will get in grams.Using a measuring cylinder, or otherwise, determine the volume of a weighed amount of****mixture**V. Measured in cc.Calculate the density**mixture**, dividing its mass per volume, ρ = m / V.The resu 3

PrimerPri two metals smelting received 400 g of an alloy of 50 cc.Determine its density

**.Calculate the density from the formula ρ = 400/50 = 8 g / cc or 8000 kg / m³.** 4

If you know the density of the substances to be mixed, and the volume, as it often occurs when mixing liquids, calculate the density of

**resulting mixture****.Measure the volume of the mixture****.It may look slightly different from the total volume of mixed liquids.For example, by mixing one liter of alcohol and 1 liter of water volume****mixture is less than 2 liters.This is due to the molecular structure of these two liquids.** 5

If the density of the mixed liquids are unknown, find their meaning in a special table.To calculate the sum of the products get the density of each of the liquids on its volume ρ1 ∙ V1 + ρ2 ∙ V2 + ρ3 ∙ V3 + ... etc.The resulting value divide by the total volume of the mixture

**V, ρ = (ρ1 ∙ V1 + ρ2 ∙ V2 + ρ3 ∙ V3 + ...) / V.** 6

PrimerPri mixing 1 liter of water and 1 liter of ethyl alcohol obtained 1.9 liters

**mixture**.Determine its density**.The density of water is 1 g / cc, alcohol - 0.8 g / cm³.Turn the unit volume: 1 l = 1000 cc, 1900 cc = 1.9.Calculate the density****mixture of the two components of the formula for ρ = (ρ1 ∙ V1 + ρ2 ∙ V2) / V = (1 ∙ 1000 + 0,8 ∙ 1000) / 1900≈0,947 g / cm³.**