you need

- capacitor voltmeter

Guide

1

To find

Q = UC, where:

Q -

U - the voltage source voltage, in volts,

C - capacity capacitor

Note that the above formula determines the amount of the charge

**charge****capacitor**, connected to a DC voltage, multiply the capacity**capacitor**on the voltage,ieuse the formula:Q = UC, where:

Q -

**charge****capacitor**, in coulombs,U - the voltage source voltage, in volts,

C - capacity capacitor

**, in farads.**Note that the above formula determines the amount of the charge

**a fully charged capacitor****.But as****charge**ka**capacitor**happening fast enough in practice use of this particular pattern. 2

power supply voltage can be measured by a voltmeter.To do this, switch the mode to measure the DC voltage terminals and connect the device to a voltage source.Record readings in volts.

3

Learn
he unit capacity farad (F) - very big, so in practice is rarely used.To denote the capacitors used smaller units.It microfarads (uF), which is equal to one millionth of Faraday and PF (PF), which is equal to one millionth of a microfarad.

1 uF = 10-6 F, 1 pF = 10-12 F.

sometimes used and the intermediate unit of capacity - Nanofarad equal to one billionth of a Farad.

1 nF = 10-9 F.

**capacity capacitor**can read marks on his body.Note that t1 uF = 10-6 F, 1 pF = 10-12 F.

sometimes used and the intermediate unit of capacity - Nanofarad equal to one billionth of a Farad.

1 nF = 10-9 F.

4

If the condenser is small, its capacity is indicated by symbols.Read

marking

For example, the inscription "60" will mean the capacity of 60 pF.

marking

**capacitor**, drawing attention to his tsvet.Esli the capacitor specified just two digits, it is its capacity in picofarads.For example, the inscription "60" will mean the capacity of 60 pF.

5

If the capacitor contains one uppercase letters or numbers, you find in the table below the corresponding numeric znachenieA 1.0 I 1.8 R 3.3 Y 5.6

B 1.1 J 2.0 S 3.6 Z 6.2

C 1.2 K 2.2 T3.9 3 6.8

D 1.3 L 2.4 V 4.3 4 7.5

E 1.5 N 2.7 W 4.7 7 8.2

H 1.6 O 3.0 X 5.1 9 9.1i, depending on the color

Black - 10

Green - 100

Blue - 1.000

Purple - 10.000

Red - 100.000Naprimer:

H on orange condenser - 1.6 * 1 = 1.6 pF

E on a green capacitor - 1.5 * 100 = 150

9 pF capacitor on blue - 9.1 * 1000 = 9100 pF

B 1.1 J 2.0 S 3.6 Z 6.2

C 1.2 K 2.2 T3.9 3 6.8

D 1.3 L 2.4 V 4.3 4 7.5

E 1.5 N 2.7 W 4.7 7 8.2

H 1.6 O 3.0 X 5.1 9 9.1i, depending on the color

**capacitor**, multiply it by the appropriate factor: Orange - 1Black - 10

Green - 100

Blue - 1.000

Purple - 10.000

Red - 100.000Naprimer:

H on orange condenser - 1.6 * 1 = 1.6 pF

E on a green capacitor - 1.5 * 100 = 150

9 pF capacitor on blue - 9.1 * 1000 = 9100 pF

6

If the capacitor is found an inscription, consisting of one uppercase letter and standing next to the figures, find in the table below the corresponding (this letter) numeric value and multiply it by 10 to the extent that is listed after bukvy.A G 10 18 N 33 56 U

B 11 H 20 P 36 V 62

C 12 J 22 Q 39 W 68 D 13 K

24 R 43X 75

E 15 L 27 S 47 Y 82

F 16 M 30 T 51 Z 91Naprimer:

B1 - 11 * (10) = 110 pF

F3 - 16 * (10 * 10 * 10) = 16,000 pF = 16nF= 0.016 uF

B 11 H 20 P 36 V 62

C 12 J 22 Q 39 W 68 D 13 K

24 R 43X 75

E 15 L 27 S 47 Y 82

F 16 M 30 T 51 Z 91Naprimer:

B1 - 11 * (10) = 110 pF

F3 - 16 * (10 * 10 * 10) = 16,000 pF = 16nF= 0.016 uF

# Tip 2: How to find the charge

The problems in physics is sometimes necessary to find

**charge any body based on its interaction with the electric field, or other bodies.In most cases, the dimensions of the body are neglected, not to count the distribution of elementary****charge**s on its mass or surface.

Guide

1

For example, how to find

**charge**speck weighing 1 mg which flew in a uniform electric field of 100 kV / m, flew 4 cm and thus its speedIt increased from 1 m / s to 3 m / s? 2

make a brief record of the task conditions: m = 1 mg, V1 = 1 m / s, V2 = 3 m / s, S = 4cm, E = kV / m, q-?

3

equate strength informing dust particle acceleration to the force acting on a speck of dust on the part of a uniform electric field.From this equation algebraically express

**charge**mote: it turns out that the product of mass and acceleration of a speck of dust motes equal to the product of the electric field and the charge**well;eventually****charge**dust particles is the ratio of product weight mote and accelerate to the value of the electric field. 4

Record kinematic equation for determining the acceleration of dust particles: acceleration is defined as the ratio of the difference of squares of the final and initial velocity to twice the value of the path traveled by a particle of dust.

5

Put this equation in the expression for the charge

**a speck of dust.The final charge****dust particles equals the product of the mass of dust particles and the difference between the squares of the final and initial velocity to twice the product of the distance traveled, and the electric field.** 6

Check dimension of the unknown quantity: it into the final formula to determine

**charge**instead of letters indicating physical quantities, substitute physical units expressed in SI units: unit**charge**and is defined asThe ratio of product kg • (m / s) to the product of 2 m • V / m;cut in the same unit fraction;Use the definition of physical quantities 1 Newton and Joel 1 and replace certain combinations of physical quantities. 7

Substituting numerical values, calculate

**charge**motes.Get q = 10 nC Helpful Hint

Notes: according to Newton's second law tells speck acceleration resultant of all forces acting on a speck of dust;because of the resistance movement of the dust particles is not mentioned, it acts only power - from the electric field.

1 Newton: [1H] = [kg ∙ m / s2];[J] = [N ∙ m];[J / V] = [Cl]

Substituting numerical values set the values of all the physical quantities in the SI;the translation of certain values in order to avoid very bulky or awkward numbers using decimals as a factor of 10 in the number of positive or negative power.

1 Newton: [1H] = [kg ∙ m / s2];[J] = [N ∙ m];[J / V] = [Cl]

Substituting numerical values set the values of all the physical quantities in the SI;the translation of certain values in order to avoid very bulky or awkward numbers using decimals as a factor of 10 in the number of positive or negative power.