- - paper;
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To find titer and on solute (simple titer ), use the formula: T = m / V, where T - titer ;m - mass of a substance dissolved in a liquid, V - the volume of solution in cubic centimeters or milliliters.
addition, titer you can calculate on the analyte.This value is also called a conditional titer th.This will require the formula: T (a / b) = mb / Va, where T (a / b) - titer a solution of the substance for substance b;mb - material mass b (in grams) is reacted with the solution;Va - volume of a solution of the substance (in milliliters).
For example, to find titer phosphoric acid solution weighing 18 g, prepared by dissolution in H3PO4 282 milli
liters of water.The density of the solution is 1.031 g / ml.First, find the mass of the prepared solution, taking into account that 282 ml of water are equal to 282 g: 28 + 282 = 300 (d).Then, calculate its volume: 300 / 1,031 = 291 (ml).Now substitute in the formula and find titer : 18/291 = 0,0619 (g / ml).
addition to the methods described above, you can also calculate the titer , knowing the equivalent weight and normal (equivalent concentration) .T = CH * Mekv / 1000, where T - titer , Tn - normality, Mekv - the equivalent weight.
Often you will encounter problems in which the need to express titer one substance over another.For example, given the condition: at titer sc 20 ml of a solution of hydrochloric acid titer ohm 0.0035 g / mL has been spent with 25 ml sodium hydroxide solution.It is necessary to calculate the titer NaOH by HCl.
Please write reaction equation: NaOH + HCl = NaCl + H2O.Then calculate titer alkali solution according to the formula: T (NaOH) = T (HCl) * V (HCl) * M (NaOH) / M (HCl) * V (NaOH).Substituting numerical values, get titer of sodium hydroxide equal to 0.0031 g / ml.It remains to calculate the required value for the solution of the problem: T (NaOH / HCl) = T (NaOH) * Meq (HCl) / Meq (NaOH) = 0,0028 g / ml
Although the same unit, never confuse the titer of the solution to its density.Because the density value shows the mass of one cubic centimeter of the solution rather than the mass of the solute therein.