Suppose you put in front of such a task.There is a solution of ammonia at a concentration of 0.1M.According to the results of laboratory tests do you know that the concentration of undissociated molecules of alcohol is equal to 0.099 mol / liter.What will be the degree of dissociation ?
First of all, remember to determine the degree dissociation and the formula by which it is calculated: a = n / N, where n - number of molecules of the substance, broken into ions and N - the total number of molecules of the substance.
Then write the equation of the electrolytic dissociation ammonia, it would look like this: NH4OH = NH4 + + OH-
Under the terms of the problem is known initial molar concentration of alcohol.Label it with the letter C. Then, the concentration of the alcohol molec
ules undergoing dissociation , designate as a speaker.Accordingly, the concentration of NH4 + ions and OH- will also be equal to this value, i.e. AC.
Determine what is the value of the AU.It is not difficult to understand that 0.001 mol / liter (you get this value by subtracting from the initial concentration of total alcohol concentration is not broken molecules).Consequently, the desired value is: 0.001 / 0.1 = 0.01.The problem is solved. degree dissociation of ammonia under specified conditions is equal to 0.01 (or 1%, in another year).