Guide

1

If there are two

**solution**, one with a concentration - and the other - with interest, for the preparation of V milliliters**solution**given**concentration**b (provided that band less, but more with), take x milliliters of a percent**solution**and (V - x) with milliliters per cent**solution**.Given that a & gt; b & gt; c, compose the equation, from which then find x: s + c • (V - x) = bV, then x = V • (bc) / (ac). 2

If you take over a 0, the previous equation takes the form x = V • b / a, ml.Podstavte required values and solve this equation.So you get, how much of the need to take stock solution to prepare the solution

**given****concentration**. 3

for dilution of concentrated solutions use the rule of mixing.For example, for the preparation of b percentage

**solution**take two**solution with concentration and with interest, provided that a & gt; b** 4

Record the condition and the result is.Please note the concentration prepared

**solution**(b) and diagonally from the bottom up to the right of this value will record one of the answers, which refers to a% solution obtained by the difference between the predetermined concentrations (b-c), and from top to bottom right, record the second answer(a-b), with relation to the% solution.The resulting need to record the answers in front of the respective solutions, ie,in front of x and y. 5

For clarity, to get 30% (x - p-p with conc. And%) and 15% (p-p at a conc. With%) solutions of 20% (b),follow the steps described above: 20-15, and 30-20 = 5 = 10.Thus, for the preparation of a solution of 20%

**mix 5 parts of 30% solution and 10 parts of 15% solution.The result was a 15 parts of a 20% solution.** Sources:

- preparation of solutions given concentration